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Byju's Answer
Standard XII
Mathematics
Plotting
The equation ...
Question
The equation of the locus of all points equidistant from the point (4, 2) and x-axis is
A
x
2
+
8
x
+
4
y
−
20
=
0
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B
x
2
+
8
x
+
4
y
+
20
=
0
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C
x
2
−
4
y
−
8
x
+
20
=
0
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D
None of these
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Solution
The correct option is
C
x
2
−
4
y
−
8
x
+
20
=
0
Suggest Corrections
0
Similar questions
Q.
The circle
x
2
+
y
2
−
8
x
+
4
y
+
4
=
0
touches:
Q.
Let
P
be the point
(
1
,
0
)
and
Q
be a point on the curve
y
2
=
8
x
. Then the locus of the mid-point of
P
Q
is
Q.
The length of the common chord of the two circles
x
2
+
y
2
−
4
y
=
0
and
x
2
+
y
2
−
8
x
−
4
y
+
11
=
0
is
Q.
The equation of the circle having centre (1, –2) and passing through the point of intersection of the lines 3x + y = 14 and 3x + 5y = 18 is
(a) x
2
+ y
2
– 2x + 4y – 20 = 0
(b) x
2
+ y
2
– 2x – 4y – 20 = 0
(c) x
2
+ y
2
+ 2x – 4y – 20 = 0
(d) x
2
+ y
2
+ 2x + 4y – 20 = 0
Q.
The equation of a parabola is given by
x
2
−
8
x
−
4
y
+
32
=
0
. Then
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