Question

The equation of the median through the vertex $A$ of triangle $ABC$ whose vertices are $A(2,5),B(-4,9)$ and $C(-2,-1)$ is

• A. $x-5y+23=0$
• B. $7x+4y-34=0$
• C. $8x-y+11=0$
• D. $x+3y-17=0$

Answer 1

The correct option is A $x-5y+23=0$

Given : $A(2,5),B(-4,9)$ and $C(-2,-1)$
Let $D$ be the mid-point of $BC$


$D\equiv (-3,4)$
So equation of $AD$ is
$y-5=\frac{4-5}{-3-2}(x-2)$
$\Rightarrow y-5=\frac{1}{5}(x-2)$
$\Rightarrow x-5y+23=0$