The equation of the normal at t-2 to the curve x-2sin t- y-2cos t is-

The correct option is B y=0 dx = 2cos t , dy = 2sin t dxdy = t dxdy = t Slope #160; = 0 as it is x axisHence, y = 0 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equation of Tangent at a Point (x,y) in Terms of f'(x)

The equation ...

Question

The equation of the normal at $t = \frac{π}{2}$ to the curve $x = 2 sin t, y = 2 cos t$ is?

x = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

y = 2 x + 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

y = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x = 2 cos t + 2 t sin t, y = 2 sin t - 2 t cos t

t = \frac{π}{4}

x = 2 cos t + 2 t sin t,

y = 2 sin t - 2 t cos t

t = \frac{π}{4}

x = 2 cos t + 2 t sin t, y = 2 sin t - 2 t cos t, at t = \frac{π}{4}

x = 2 cos t + 2 t sin t, y = 2 sin t - 2 t cos t, at t = \frac{π}{4}

x = 2 cos t - cos 2 t

y = 2 sin t - sin 2 t

y

(t = \frac{π}{2})

Join BYJU'S Learning Program