wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the normal to the circle x2+y2−2x=0 parallel to the line x+2y=3 is

A
x+2y+3=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x+2y3=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+2y1=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x+2y+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C x+2y1=0
Given circle is x2+y22x=0
Centre of the circle, C=(1,0)
Any line parallel to the line x+2y=3 is
x+2y+k=0
As this is normal, so it passes through the centre C(1,0)
1+2(0)+k=0k=1
Therefore, the equation of normal is
x+2y1=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon