The correct option is C x+2y−1=0
Given circle is x2+y2−2x=0
Centre of the circle, C=(1,0)
Any line parallel to the line x+2y=3 is
x+2y+k=0
As this is normal, so it passes through the centre C(1,0)
1+2(0)+k=0⇒k=−1
Therefore, the equation of normal is
x+2y−1=0