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Question

The equation of the normal to the curve y=sinπx2 at (1,1) is

A
y = 1
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B
x = 1
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C
y = x
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D
y1=1π(x1)
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Solution

The correct option is B x = 1
y=sinπx2dydx=π2cosπx2dydx(x,y)=(1,1)=0Slope of normal =Normal is to Y-axisNormal is x=1

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