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Question

The equation of the parabola whose vertex and focus lie on the axis of x at distances a and a1 from the origin respectively is:

A
y2=4(a1a)x
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B
y2=4(a1a)(xa)
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C
y2=4(a1a)(xa1)
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D
none of these
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Solution

The correct option is B y2=4(a1a)(xa)
Vertex A is (a,0)
Focus S is (a1,0)
Distance between vertex and focus AS=a1a=A(say)
So, the equation of parabola with vertex at (a,0) is
(y0)2=4A(xa)
(y0)2=4(a1a)(xa)
y2=4(a1a)(xa)

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