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Question

The equation of the passing through the points (2, -1, 0), (3 ,-4, 5) and parallel to the line 2x=3y=4z is

A
125x90y79z=340
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B
32x21y36z=85
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C
73x+61y22z=85
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D
29x27y22z=85
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Solution

The correct option is D 29x27y22z=85
we get
x12=y13=z14
a(x2)+b(y+1)+cz=0
a2+b3+c4=0 [planeisparalleltoline]
6a+4b+3c=0
a3b+5c=0 [planepassingthorugh(3,4,5)]
a20+9=b303=c184
a29=b27=c22
29x27y22z=58+27
29x27y22z=85
Hence, the option D is the correct answer.

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