Question

The equation of the plane containing the line of intersection of the planes 2x - y = 0 and y - 3z = 0 and perpendicular to the plane 4x + 5y - 3z - 8 = 0 is

• A.
  
• B.
  
• C.
  
• D.
  

Answer 1

The correct option is A

Equation of plane containing the line of intersection of planes is, (2x - y) + $\lambda$(y - 3z) = 0 ..............(i)
Also, plane (i) is perpendicular to
4x + 5y - 3z - 8 = 0
$\therefore 4\left(2\right)+5(\lambda -1)-3(-3\lambda )=0$
$\Rightarrow 14\lambda =-3\Rightarrow \lambda =-\frac{3}{14}$
Put the value of $\lambda$ in (i), we get
28x - 17y + 9z = 0, which is the require plane.