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Question

The equation of the plane parallel to the plane 2x+3y+4z+5=0 and passing through the point (1,1,1) is:

A
2x+3y+4z+9=0
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B
2x+3y+4z9=0
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C
2x+3y+4z+7=0
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D
2x+3y+4z7=0
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Solution

The correct option is B 2x+3y+4z9=0
The equation of the plane parallel to the plane 2x+3y+4z+5=0 will have normal D.Rs=(2,3,4)
Hence the equation of plane passing through (1,1,1) is 2(x1)+3(y1)+4(z1)=0
Hence we have 2x+3y+4z9=0

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