The equation of the plane parallel to the plane 2x+3y+4z+5=0 and passing through the point (1,1,1) is:
A
2x+3y+4z+9=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2x+3y+4z−9=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
2x+3y+4z+7=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2x+3y+4z−7=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B2x+3y+4z−9=0 The equation of the plane parallel to the plane 2x+3y+4z+5=0 will have normal D.R′s=(2,3,4)
Hence the equation of plane passing through (1,1,1) is 2(x−1)+3(y−1)+4(z−1)=0
Hence we have 2x+3y+4z−9=0