The equation of the plane passing through a point with position vector ^i+2^j+3^j and parallel to the plane →r.(3^i+4^j+5^j)
A
3x+4y−5Z+26=0
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B
3x+4y+5z−26=0
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C
3x−4y+5z−26=0
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D
3x+4y−5Z−26=0
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Solution
The correct option is B3x+4y+5z−26=0 Since, the plane is parallel to the given plane, The equation of plane is 3x+4y+5z=d The plane passes through the point (1,2,3). ∴3(1)+4(2)+5(3)=d So, the value of d=26 Hence, equation of the plane is 3x+4y+5z−26=0