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Question

The equation of the plane passing through the lines x41=y31=z22 and x31=y24=z5 is-

A
11xy3z=35
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B
11x+y3z=35
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C
11xy+3z=35
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D
None of these.
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Solution

The correct option is D None of these.
Normal vector of the plane is given by,
n=∣ ∣ ∣^i^j^k112145∣ ∣ ∣=9^i3^j5^k
Hence equation of plane is,
(r(3^i+2^j))n=0
9x3y5z21=0

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