The equation of the plane passing through the point -1-2-0 and parallel to the lines L 1- x -3- y -1-0- z -2-1 and L 2- x -1-1-2 y -1-2-z -1-1 isA- x-2 y-3 z-3B- x-2 y-3 z-3-0C- x-2 y-3 z-3D- x-2 y-3 z-3

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equation of Line: Symmetrical Form

The equation ...

Question

The equation of the plane passing through the point $(- 1, 2, 0)$ and parallel to the lines $L_{1} : \frac{x}{3} = \frac{y + 1}{0} = \frac{z - 2}{- 1}$ and $L_{2} : \frac{x - 1}{1} = \frac{2 y + 1}{2} = \frac{z + 1}{- 1}$ is

x + 2 y + 3 z = 3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x - 2 y + 3 z = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 2 y + 3 z + 3 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x + 2 y - 3 z = 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $x + 2 y + 3 z = 3$
Equartion of the plane through $(- 1, 2, 0)$ is
$a (x + 1) + b (y - 2) + c z = 0$
$∵$ plane is parallel to the lines
$∴ 3 a - c = 0, a + b - c = 0 b = 2 a, c = 3 a$
equation of the plane is $x + 2 y + 3 z = 3$

Suggest Corrections

Similar questions

Q. Equation of the line passing through the point

(2, 3, 1)

and parallel to the line of the intersection of the plane

x - 2 y - z + 5 = 0 and x + y + 3 z = 6

Q. Equation of the plane containing the line

x + 2 y + 3 z - 5 = 0 = 3 x + 2 y + z - 5

which is parallel to the line

x - 1 = 2 - y = z - 3

, is-

Q. Equation of the plane perpendicular to the line

\frac{x - 1}{3} = \frac{y - 5}{2} = \frac{z + 3}{- 4}

and passing through the point

(1, - 2, 3)

The equation of a plane passing through the line of intersection of the planes $x + 2 y + 3 z = 2$ and $x - y + z = 3$ and at a distance $\frac{2}{\sqrt{3}}$ from the point (3,1,-1) is

Q. The equation of the line passing through the point (1, 1, –1) and perpendicular to the plane x – 2y – 3z = 7 is

Join BYJU'S Learning Program

The equation of the plane passing through the point (−1,2,0) and parallel to the lines L1:x3=y+10=z−2−1 and L2:x−11=2y+12=z+1−1 is

The correct option is A x+2y+3z=3 Equartion of the plane through (−1,2,0) is a(x+1)+b(y−2)+cz=0 ∵ plane is parallel to the lines ∴3a−c=0,a+b−c=0b=2a, c=3a equation of the plane is x+2y+3z=3

The equation of the plane passing through the point $(- 1, 2, 0)$ and parallel to the lines $L_{1} : \frac{x}{3} = \frac{y + 1}{0} = \frac{z - 2}{- 1}$ and $L_{2} : \frac{x - 1}{1} = \frac{2 y + 1}{2} = \frac{z + 1}{- 1}$ is

The correct option is A $x + 2 y + 3 z = 3$
Equartion of the plane through $(- 1, 2, 0)$ is
$a (x + 1) + b (y - 2) + c z = 0$
$∵$ plane is parallel to the lines
$∴ 3 a - c = 0, a + b - c = 0 b = 2 a, c = 3 a$
equation of the plane is $x + 2 y + 3 z = 3$