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Question

The equation of the plane passing through the points P(1,1,1),Q(3,1,2),R(3,5,4) is

A
x+y=2
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B
y+z=2
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C
z+x=2
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D
x+y+z=2
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Solution

The correct option is A x+y=2
Equation of plane is:
∣ ∣xx1yy1zz1x2x1y2y1z2z1x3x1y3y1z3z1∣ ∣=0

Here, given points are
P(1,1,1),Q(3,1,2),R(3,5,4)
So equation of plane is

∣ ∣x1y1z1311121315141∣ ∣=0∣ ∣x1y1z1221445∣ ∣=0(x1)(104)(y1)(10+4)+(z1)(88)=0(x1)6(y1)(6)=0x+y=2

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