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Byju's Answer
Standard XII
Mathematics
Relative Position of a Point with Respect to a Line
The equation ...
Question
The equation of the plane passing through the points
P
(
1
,
1
,
1
)
,
Q
(
3
,
−
1
,
2
)
,
R
(
−
3
,
5
,
−
4
)
is
A
x
+
y
=
2
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B
y
+
z
=
2
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C
z
+
x
=
2
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D
x
+
y
+
z
=
2
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Solution
The correct option is
A
x
+
y
=
2
Equation of plane is:
∣
∣ ∣
∣
x
−
x
1
y
−
y
1
z
−
z
1
x
2
−
x
1
y
2
−
y
1
z
2
−
z
1
x
3
−
x
1
y
3
−
y
1
z
3
−
z
1
∣
∣ ∣
∣
=
0
Here, given points are
P
(
1
,
1
,
1
)
,
Q
(
3
,
−
1
,
2
)
,
R
(
−
3
,
5
,
−
4
)
So equation of plane is
∣
∣ ∣
∣
x
−
1
y
−
1
z
−
1
3
−
1
−
1
−
1
2
−
1
−
3
−
1
5
−
1
−
4
−
1
∣
∣ ∣
∣
=
0
⇒
∣
∣ ∣
∣
x
−
1
y
−
1
z
−
1
2
−
2
1
−
4
4
−
5
∣
∣ ∣
∣
=
0
⇒
(
x
−
1
)
(
10
−
4
)
−
(
y
−
1
)
(
−
10
+
4
)
+
(
z
−
1
)
(
8
−
8
)
=
0
⇒
(
x
−
1
)
6
−
(
y
−
1
)
(
−
6
)
=
0
⇒
x
+
y
=
2
Suggest Corrections
0
Similar questions
Q.
Find equation of the plane passing through the points
P
(
1
,
1
,
1
)
,
Q
(
3
,
−
1
,
2
)
,
R
(
−
3
,
5
,
−
4
)
?
Q.
A plane passes through the points P (1,1,1) , Q (3, -1, 2) and R (-3, 5 , -4). The equation of the plane is
.