The equation of the plane through the intersection of the planes x+2y+3z−4=0 and 4x+3y+3z+1=0 and passing through the origin is-
A
17x+14y+15z=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
7x+4y+z=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+14y+11z=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
17x+y+z=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C17x+14y+15z=0 Equation of plane passing through intersection of given plane is given by, P1+λP2=0⇒(x+2y+3z−4)+λ(4x+3y+3z+1)=0 Given it also passes through origin ⇒−4+λ=0⇒λ=4 Hence required plane is, 17x+14y+15z=0