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Question

The equation of the plane which bisect the join of point (7,2,3) and (1,4,3) perpendicularly is

A
x+2y+3=0
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B
2xy+3=0
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C
x+y+2z+7=0
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D
4x+3y=9
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Solution

The correct option is D 4x+3y=9
Lets assume P=(7,2,3) and Q=(1,4,3)
So mid point of PQ is(3,1,3)=M (say), since plane bisect PQ so M will lie in required plane.
Also direction ratios of PQ are 8,6,0.
Also given PQ is perpendicular to the plane, thus equation of plane is given by,
8(x3)+6(y+1)+0(z3)=0
4x+3y9=0

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