The equation of the plane which is parallel to 2x – 3y + 5z + 7 = 0 and passing through the point (3, 4, -1) is

2x – 3y + 5x – 7 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2x – 3y + 5z + 9 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2x – 3y + 5z + 11 = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2x – 3y + 5z – 11 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
2x – 3y + 5z + 11 = 0

The equation of plane is 2x-3y+5x+k=0 which passes through $(3, 4, - 1) \Rightarrow k = 11$

Suggest Corrections

Similar questions

(3, 4, - 1)

2 x - 3 y + 5 z - 7 = 0

2 x + 3 y + 5 z + 1 = 0

(1, 2, - 3)

x + y + z + 1 = 0

2 x - 3 y + 5 z - 2 = 0

(- 1, 2, 1)

(- 1, 0, 1)

2 x - 3 y + z + 1 = 0,

Join BYJU'S Learning Program