The equation of the plane which is parallel to the plane x-2y+2z=5 and whose distance from the point (1,2,3) is 1, is
A
x-2y+2z=3
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B
x-2y+2z+3=0
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C
x-2y+2z=6
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D
x-2y+2z+6=0
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Solution
The correct option is C x-2y+2z=6 Equation of plane parallel to x-2y+2z=5 is x-2y+2z+k=0
Now, according to question, 1−4+6+k√9=±1
or k+3=±3⇒ k = 0 or -6 ∴ x-2y+2z-6=0 or x-2y+2z=6.