Question

The equation of the plane which is parallel to the plane x-2y+2z=5 and whose distance from the point (1,2,3) is 1, is

• A. x-2y+2z=3
• B. x-2y+2z+3=0
• C. x-2y+2z=6
• D. x-2y+2z+6=0

Answer 1

The correct option is C x-2y+2z=6

Equation of plane parallel to x-2y+2z=5 is x-2y+2z+k=0
Now, according to question, $\frac{1-4+6+k}{\sqrt{9}}=\pm 1$
or $k+3=\pm 3\Rightarrow$ k = 0 or -6
$\therefore$ x-2y+2z-6=0 or x-2y+2z=6.