Question

The equation of the plane with intercepts $2,3,4$ on the $x,y$ and $z$ axes respectively is

• A. $2x+3y+4z=1$
• B. $2x+3y+4z=12$
• C. $6x+4y+3z=1$
• D. $6x+4y+3z=12$

Answer 1

The correct option is D $6x+4y+3z=12$

The equation of the plane with intercepts $a,b,c$ is given as
$\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1$
$\therefore$ The equation of plane with intercepts $2,3,4$ is :
$\frac{x}{2}+\frac{y}{3}+\frac{z}{4}=1$
$\Rightarrow 6x+4y+3z=12$