The equation of the polar of $(- 2, 3)$ w.r.t. $x^{2} + y^{2} - 4 x - 6 y + 5 = 0$

x = y

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x + y = 0

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x = 0

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y = 0

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Solution

The correct option is C $x = 0$
Equation of polar of $P (x_{1}, y_{1})$ to circle $x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ is
$T = 0$
$∴ e q^{n}$ of polar of $(- 2, 3)$ w.r.t. $x^{2} + y^{2} - 4 x - 6 y + 5 = 0$
$x (- 2) + y (3) - 2 (x - 2) - 3 (y + 3) + 5 = 0$
$- 4 x + 9 - 9 = 0$
$\Rightarrow x = 0$

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