wiz-icon
MyQuestionIcon
MyQuestionIcon
1689
You visited us 1689 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the smallest degree with real coefficients having 1 + i as one of the roots is


A

x2+x+1=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

x22x+2=0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

x2+2x+2=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

x2+2x2=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

x22x+2=0


We know that, imaginary roots of a quadratic equation occur in conjugate pair.

It is given, that, 1 + i is one of the roots.

So, the other root will be 1 - i.

Thus, the quadratic equation having roots 1 + i and 1-i is,

x2(1+i+1i)x+(1+i)(1i)=0x22x+2=0


flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Nature and Location of Roots
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon