Question

The equation of the straight line passing through the intersection of the lines $x-y-1=0$ and $2x-3y+1=0$ and parallel to $3x+4y-14=0$ is

• A. $3x+4y=-24$
• B. $3x+4y=24$
• C. $4x+3y=24$
• D. $3x+4y=12$

Answer 1

The correct option is B $3x+4y=24$

Intersection point of the lines $x-y-1=0$ and $2x-3y+1=0$
is $(4,3)$
Now equation of line parallel to $3x+4y-14=0$ is
$3x+4y+c=0$
$\because$ it passes through $(4,3)$
$\therefore c=-24$
Hence line will be $3x+4y=24$