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Question

The equation of the straight line passing through the point (3,2) and perpendicular to the line y=x is

A
x+y=1
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B
xy=5
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C
x+y=5
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D
xy=1
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Solution

The correct option is C x+y=5
Given line : y=x

Slope is 1,

If two lines are perpendicular, then product of their slopes =1

So, slope of the line perpendicular to given line is 1.

Therefore, equation of line passing through (3,2) and having slope 1 is

y2=1(x3)

y2=x+3

x+y=5

Hence, option (B) is correct.

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