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Question

The equation of the straight line which is perpendicular to 7x−8y=6 is

A
8x+7y=3
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B
7x+8y=3
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C
8x7y=3
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D
7x8y=3
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Solution

The correct option is A 8x+7y=3
Given
7x8y=6
The slope of the given line is m1=78
Let slope of line perpendicular be m2
if two lines are perpendicular then
m1m2=1
78×m2=1
m2=87
hence the slope of line perpendicular line will be 87.
eq of line will be with slope 87
and option A has the same slope

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