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Question

The equation of the straight line which passes through the point (3, 4) and whose intercept on y-axis is twice that on x-axis, is


A

2x – y = 10

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B

x + 2y = 10

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C

2x + y = 10

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D

None of these

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Solution

The correct option is C

2x + y = 10


Let the equation of the line be

xa+yb=1......(1)

Given: intercept on y-axis = 2 (intercept on x-axis)

i.e., b = 2a

So, equation (1) becomes

xa+y2a=1

2x+y=2a(2)

Since line (2) passes through the point (3, 4)

2×3+4=2aa5

Thus, the equation of the required line is

2x+y=10


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