The equation of the straight line whose intercepts on x-axis and y-axis are respectively twice and thrice of those by the line 3x+4y=12, is
A
9x+8y=72
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B
9x−8y=72
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C
8x+9y=72
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D
8x+9y+72=0
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Solution
The correct option is A9x+8y=72 Given line is, 3x+4y=12 ⇒x4+y3=1⇒(1) Thus intercepts on the axes by line (1) are 4 and 3 respectively So, the intercept on the axes of required line will be 8 and 9 respectively, Hence it's equation is given by, x8+y9=1⇒9x+8y=72