Question

The equation of the tangent at the vertex of the parabola $x^2+4x+2y=0$ is

• A. $x=-2$
• B. $x=2$
• C. $y=2$
• D. $y=-2$

Answer 1

The correct option is C $y=2$

Given that
$x^2+4x+2y=0$
$x^2+4x+2y+4-4=0$
$(x+2{)}^2=-2(y-2)$
Which is of the form
$X^2=-2Y$
So,the equation of tangent at vertex is $Y=0$
i.e.,$y-2=0$
$\Rightarrow y=2$