The equation of the tangent at the vertex of the parabola $x^{2} + 4 x + 2 y = 0$ is

x = - 2

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x = 2

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y = 2

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y = - 2

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Solution

The correct option is B $y = 2$
The Equation of tangent at vertex to parabola $x^{2} + 4 x + 2 y = 0$ is :
$x^{2} + 4 x + 2 y + 4 - 4 = 0 (x + 2)^{2} = - 2 (y - 2) x^{2} = - 2 y$
Equation of tangent at vertex is $y = 0$
$y - 2 = 0$
$y = 2$

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