The equation of the tangent to the circle $x^{2} + y^{2} - 4 x - 6 y - 12 = 0$ at $(2, 8)$ is

y = 8

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x = 8

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y + 8 = 0

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x + 80

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Solution

The correct option is A $y = 8$
Equation of circle is $x^{2} + y^{2} - 4 x - 6 y - 12 = 0$
$g = - 2, f = - 3, x_{1} = 2, y_{1} = 8$
Equation of tangent $(x_{1} + g) x + (y_{1} + f) y + (g x_{1} + f y_{1} + c) = 0 (2 - 2) x + (8 - 3) y + (- 4 - 24 - 12) = 0 5 y - 40 y = 8$

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Similar questions

x^{2} + y^{2} - 4 x + 6 y - 12 = 0

x + y - 8 = 0

Equation of smallest circle passing through points of intersection of line $x + y = 1$ & circle $x^{2} + y^{2} = 9$ is

x^{2} + y^{2} - 4 x + 6 y + 10 = 0

4 x - 3 y + 8 = 0

y^{2} = 24 x

x^{2} + y^{2} = 18

x^{2} + y^{2} + 4 x + 6 y + 8 = 0

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