The equation of the tangent to the conic x2-y2-8 x-2 y-11-0 at 2-1 is-A- y-1B- x-2C- x-y-3 D- 2 x-y-3

The correct option is B x = 2The equation of tangent nbsp; to curve x^2 y^2 8x + 2y + 11 =0 at (2,1) is T=0 ⇒2x y 4(x + 2) + (y + 1) + 11 = 0 ⇒ x = 2 ...

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Standard XII

Mathematics

Point Form of Tangent: Hyperbola

The equation ...

Question

The equation of the tangent to the conic $x^{2} - y^{2} - 8 x + 2 y + 11 = 0$ at $(2, 1)$ is:

y = 1

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x + y = 3

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x = 2

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2 x - y = 3

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Solution

The correct option is C $x = 2$
The equation of tangent to curve $x^{2} - y^{2} - 8 x + 2 y + 11 = 0$
at $(2, 1)$ is $T = 0$
$\Rightarrow 2 x - y - 4 (x + 2) + (y + 1) + 11 = 0$
$\Rightarrow x = 2$

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Point Form of Tangent: Hyperbola

Standard XII Mathematics

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The equation of the tangent to the conic x2−y2−8x+2y+11=0 at (2,1) is:

The correct option is C x=2The equation of tangent to curve x2−y2−8x+2y+11=0 at (2,1) is T=0 ⇒2x−y−4(x+2)+(y+1)+11=0 ⇒x=2

The equation of the tangent to the conic $x^{2} - y^{2} - 8 x + 2 y + 11 = 0$ at $(2, 1)$ is:

The correct option is C $x = 2$
The equation of tangent to curve $x^{2} - y^{2} - 8 x + 2 y + 11 = 0$
at $(2, 1)$ is $T = 0$
$\Rightarrow 2 x - y - 4 (x + 2) + (y + 1) + 11 = 0$
$\Rightarrow x = 2$