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Question

The equation of the tangent to the conic x2y28x+2y+11=0 at (2,1) is:

A
y=1
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B
x+y=3
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C
x=2
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D
2xy=3
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Solution

The correct option is C x=2
The equation of tangent to curve x2y28x+2y+11=0
at (2,1) is T=0
2xy4(x+2)+(y+1)+11=0
x=2

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