The correct option is D y = 2x - 1
Given equation of parabola is y=x2−2x+3.
Differentiating this w.r.t. x, we get
y' = 2x - 2.
The slope of the tangent to the parabola at (2, 3) is 2(2) - 2 = 2.
The equation of the line passing through (2, 3) and having slope 2 is y = 2x - 1.