The correct option is C y=0,y=6
Given equation of ellipse is
9x2+5y2−30y=0
The above equation can be rewritten as
9x2+5(y2−6y)=0
⇒9x2+5(y−6y+9)=45
⇒9x2+5(y−3)2=45
⇒x25+(y−3)29=1
Since, a2<b2, so axis of ellipse is Y-axis.
To find vertex at Y-axis, put x=0.
∴5(y−3)2=45
⇒(y−3)2=9
⇒y−3=±3
⇒y=0 or y=6
Therefore, tangents at vertex are y=0,y=6.