CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation of the tangents drawn at the ends of the major axis of the ellipse 9x2+5y2−30y=0 are

A
y=±3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x=±5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y=0,y=6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of the above
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C y=0,y=6
Given equation of ellipse is
9x2+5y230y=0
The above equation can be rewritten as
9x2+5(y26y)=0
9x2+5(y6y+9)=45
9x2+5(y3)2=45
x25+(y3)29=1
Since, a2<b2, so axis of ellipse is Y-axis.
To find vertex at Y-axis, put x=0.
5(y3)2=45
(y3)2=9
y3=±3
y=0 or y=6
Therefore, tangents at vertex are y=0,y=6.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Theorems for Differentiability
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon