The equation of the tangents to the circle x 2- y 2-6 x -6 y -2-0- which is parallel to 3 x -4 y -8-0 areA- 3 x -4 y -41-0-3 x -4 y -1-0B- 3 x -4 y -41-0-3 x -4 y -1-0C- 3 x -4 y -41-0-3 x -4 y -1-0D- 3 x -4 y -41-0-3 x -4 y -1-0

The correct option is B 3x+4y+41=0, 3x+4y+1=0 nbsp; nbsp;Tangent line parallel to 3x +4y+8=0 is 3x+4y+λ=0 Radius of the circle =√(g^2+f^2 c)=4 Center of ...

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Byju's Answer

Standard XII

Mathematics

Pair of Tangents from a Point

The equation ...

Question

The equation of the tangents to the circle $x^{2} + y^{2} + 6 x + 6 y + 2 = 0$ , which is parallel to $3 x + 4 y + 8 = 0$ are

3 x + 4 y + 41 = 0, 3 x + 4 y + 1 = 0

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3 x + 4 y + 41 = 0, 3 x + 4 y - 1 = 0

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3 x + 4 y - 41 = 0, 3 x + 4 y + 1 = 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 x + 4 y - 41 = 0, 3 x + 4 y - 1 = 0

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Solution

The correct option is A $3 x + 4 y + 41 = 0, 3 x + 4 y + 1 = 0$
Tangent line parallel to $3 x + 4 y + 8 = 0$ is $3 x + 4 y + λ = 0$
Radius of the circle $= \sqrt{g^{2} + f^{2} - c} = 4$

Center of the circle $(- 3, - 3)$
$4 = ∣ ∣ ∣ \frac{3 (- 3) + 4 (- 3) + λ}{5} ∣ ∣ ∣ 20 = \pm (λ - 21)$
$\Rightarrow λ = 1, 41$
Equation of tangents are
$3 x + 4 y + 1 = 0, 3 x + 4 y + 41 = 0$

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The equation of the tangents to the circle x2+y2+6x+6y+2=0, which is parallel to 3x+4y+8=0 are

The correct option is A 3x+4y+41=0, 3x+4y+1=0 Tangent line parallel to 3x+4y+8=0 is 3x+4y+λ=0 Radius of the circle =√g2+f2−c=4 Center of the circle (−3,−3) 4=∣∣∣3(−3)+4(−3)+λ5∣∣∣20=±(λ−21) ⇒λ=1,41 Equation of tangents are 3x+4y+1=0, 3x+4y+41=0

The equation of the tangents to the circle $x^{2} + y^{2} + 6 x + 6 y + 2 = 0$ , which is parallel to $3 x + 4 y + 8 = 0$ are