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Question

The equation of the transverse and conjugate axis of the hyperbola 16x2y2+64x+4y+44=0 are

A
x=2,y+2=0
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B
x=2,y=2
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C
x+2=0,y=2
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D
x+2=0,y+2=0
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Solution

The correct option is C x+2=0,y=2
(4x+8)2(y2)2=44+644

16(x+2)216(y2)216=1

So, transverse and conjugate axes equations are x+2=0,y=2 respectively.


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