Question

The equation of the transverse and conjugate axis of the hyperbola $16x^2-y^2+64x+4y+44=0$ are

• A. $x=2,y+2=0$
• B. $x=2,y=2$
• C. $x+2=0,y=2$
• D. $x+2=0,y+2=0$

Answer 1

The correct option is C $x+2=0,y=2$

$(4x+8{)}^2-(y-2{)}^2=-44+64-4$

$\Rightarrow \frac{16(x+2{)}^2}{16}-\frac{(y-2{)}^2}{16}=1$

So, transverse and conjugate axes equations are $x+2=0,y=2$ respectively.