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Question

The equation of wave is $y = 5 sin (\frac{t}{0.04} - \frac{x}{4})$ where $y$ is in centimeter, $x$ is in centimeters and $t$ is in seconds. Find the maximum velocity of the particles of the medium,

150 m / s

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100 m / s

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125 m / s

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200 m / s

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Solution

The correct option is A $125 m / s$
Given,
$y = 5 s i n (\frac{t}{0.04} - \frac{x}{4})$

velocity, $v = \frac{d y}{d t} = 5 \times \frac{1}{0.04} c o s (\frac{t}{0.04} - \frac{x}{4})$

The maximum velocity,
$v_{0} = 5 \times \frac{1}{0.04} = 125 m / s$
The correct option is C.

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The equation of wave is y=5sin(t0.04−x4) where y is in centimeter, x is in centimeters and t is in seconds. Find the maximum velocity of the particles of the medium,

The correct option is A 125m/sGiven,y=5sin(t0.04−x4)velocity, v=dydt=5×10.04cos(t0.04−x4)The maximum velocity, v0=5×10.04=125m/sThe correct option is C.

The equation of wave is $y = 5 sin (\frac{t}{0.04} - \frac{x}{4})$ where $y$ is in centimeter, $x$ is in centimeters and $t$ is in seconds. Find the maximum velocity of the particles of the medium,

The correct option is A $125 m / s$
Given,
$y = 5 s i n (\frac{t}{0.04} - \frac{x}{4})$

velocity, $v = \frac{d y}{d t} = 5 \times \frac{1}{0.04} c o s (\frac{t}{0.04} - \frac{x}{4})$

The maximum velocity,
$v_{0} = 5 \times \frac{1}{0.04} = 125 m / s$
The correct option is C.