The equations of normalss to the curve 3 x2-y2-8 which is parallel to the line x-3 y-4 is-

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Slope Form of Normal : Hyperbola

The equations...

Question

The equation(s) of normals(s) to the curve 3x² - y² = 8 which is parallel to the line x + 3y = 4 is.

3x - y + 8 = 0

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x + 3y + 8 = 0

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x + 3y + 3 = 0

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x + 3y + 18 = 0

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Solution

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Find the equation of the normal lines to the curve $3 x^{2} - y^{2} = 8$ which are parallel to the line $x + 3 y = 4.$

3 x^{2} - y^{2} = 8

2 x^{2} - y^{2} = 14

x + 3 y = 6

3 x^{2} - y^{2} = 8

(\frac{4}{3}, 0)

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