The equation(s) of tangents to the parabola y2 = 12x, which passes through the point (2,5) is/are:
A
y = x + 3
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B
y = x - 3
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C
2y = 3x - 4
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D
2y = 3x + 4
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Solution
The correct option is D 2y = 3x + 4 We know that the equation of a tangent to y2=4ax having slope m is given by- y=mx+amAsa=3⇒y=mx+3mAsthistangentpassesthroughthepoint(2,5)5=2m+3mor2m2−5m+3=0orm=1,32Onputtingthevalueofm,theequationofthetangentsare:y=x+3and2y=3x+4