The equation(s) of the line(s) which cut-off intercepts on the axes whose sum and product are 1 and -6 respectively, is/are
A
2x-3y-6 = 0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2x-3y = -6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
-3x+2y = 6
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
3x - 2y = 6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C -3x+2y = 6 Let the equation of the line be xa+yb=1
Given that a+b = 1 and ab = -6Weknowthat(a−b)2=(a+b)2−4ab⇒(a−b)2=1−4(−6)=25⇒a−b=±5CaseI.Ifa−b=5anda+b=1⇒a=3andb=−2Therefore,theequationofthelinewillbex3+y−2=1⇒−2x+3y=−6⇒2x−3y−6=0 CaseII.Ifa−b=−5anda+b=1⇒a=−2,b=3Therefore,theequationofthelinewillbex−2+y3=1⇒−3x+2y=6