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Question

The equation(s) of the line(s) which cut-off intercepts on the axes whose sum and product are 1 and -6 respectively, is/are

A
2x-3y-6 = 0
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B
2x-3y = -6
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C
-3x+2y = 6
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D
3x - 2y = 6
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Solution

The correct option is C -3x+2y = 6
Let the equation of the line be
xa+yb=1
Given that a+b = 1 and ab = -6We know that(ab)2=(a+b)24ab(ab)2=14(6)=25ab=±5Case I.If ab=5 and a+b=1a=3 and b=2 Therefore, the equation of the line will bex3+y2=12x+3y=62x3y6=0
Case II.If ab=5 and a+b=1a=2, b=3Therefore, the equation of the line will bex2+y3=13x+2y=6

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