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Question

The equation x+4- x3+ 1=0 has:

A
no root
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B
one real root
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C
one real root and one imaginary root
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D
two imaginary roots
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E
two real roots
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Solution

The correct option is C no root
x+4x3+1=0x+4+1=x3x+4+1+2x+4=x32x+4=8x+4=16x=12
But x = 12 will not satisfy given equation.
No roots for given equation.

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