Question

The equation that is incorrect is:

• A. ${\wedge }_m^{0}NaBr-{\wedge }_m^{0}NaI={\wedge }_m^{0}KBr-{\wedge }_m^{0}NaBr$
• B. ${\wedge }_m^{0}NaBr-{\wedge }_m^{0}NaCl={\wedge }_m^{0}KBr-{\wedge }_m^{0}KCl$
• C. ${\wedge }_m^{0}KCl-{\wedge }_m^{0}NaCl={\wedge }_m^{0}KBr-{\wedge }_m^{0}NaBr$
• D. ${\wedge }_m^0{H}_{2}O-{\wedge }_m^{0}HCl={\wedge }_m^{0}NaOH-{\wedge }_m^{0}NaBr$

Answer 1

The correct option is A ${\wedge }_m^{0}NaBr-{\wedge }_m^{0}NaI={\wedge }_m^{0}KBr-{\wedge }_m^{0}NaBr$

${\wedge }_m^{0}NaI-{\wedge }_m^{0}NaBr={\wedge }_m^{0}NaBr-{\wedge }_m^{0}KBr$

$[{\lambda }_m^{0}N{a}^{+}+{\lambda }_m^0{I}^{-}]-[{\lambda }_m^{0}N{a}^{+}+{\lambda }_m^{0}B{r}^{-}]=[{\lambda }_m^{0}N{a}^{+}+{\lambda }_m^{0}B{r}^{-}]-[{\lambda }_m^0{K}^{+}+{\lambda }_m^{0}B{r}^{-}]$
${\lambda }_m^0{I}^{-}-{\lambda }_m^{0}B{r}^{-}\ne {\lambda }_m^{0}N{a}^{+}-{\lambda }_m^0{K}^{+}$