Question

The equation to the locus of s point which is equidistance from the points $(2,3),(-2,5)$ is

• A. $2x-y+4=0$
• B. $2x-y-1=0$
• C. $2x+y-4=0$
• D. $2x+y+1=0$

Answer 1

The correct option is A $2x-y+4=0$

We have,

Let $A(1,1)$ and $B(3,3)$

Let (x, y) be the point (P) from both A and B

$\therefore AP=BP$

$A{P}^2=B{P}^2$

$\therefore (x-1{)}^2+(y-1{)}^2=(x-3{)}^2+(y-3{)}^2$

$x^2-2x+1+y_1^2-2y_2+1=x^2-6x+9+y^2-6y+9$

$-2x-2y+2=-6x-6y+9$

$4x+4y-7=0$

Hence, this is answer.