The equation to the pair of tangents drawn from -1-2 to parabola x 2-2 y isA- 4 x2-2 x y-y2-4 x-6 y-4-0- x2-2 x y-3 y2-10 x-6 y-9-0- 4 x2-2 x y-3 y2-4 x-6 y-4-0D- x2-2 x y-3 y2-10 x-6 y-9-0

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Pair of Tangents from an External Point

The equation ...

Question

The equation to the pair of tangents drawn from (–1, –2) to parabola $x^{2} = 2 y$ is

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Solution

The correct option is B
Equation of pair of tangents is given by $T^{2} = S S_{1}$
Equation of pair of tangents from $(- 1, - 2) i s [- x - (y - 2)^{2}] = (x^{2} - 2 y) (1 + 4)$
$\Rightarrow (- x - y + 2)^{2} = 5 (x^{2} - 2 y) \Rightarrow 4 x^{2} - y^{2} - 2 x y + 4 x - 6 y - 4 = 0$

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The equation to the pair of tangents drawn from (–1, –2) to parabola x2=2y is

The correct option is B Equation of pair of tangents is given by T2=SS1 Equation of pair of tangents from (−1,−2)is[−x−(y−2)2]=(x2−2y)(1+4) ⇒(−x−y+2)2=5(x2−2y)⇒4x2−y2−2xy+4x−6y−4=0

The equation to the pair of tangents drawn from (–1, –2) to parabola $x^{2} = 2 y$ is

The correct option is B
Equation of pair of tangents is given by $T^{2} = S S_{1}$
Equation of pair of tangents from $(- 1, - 2) i s [- x - (y - 2)^{2}] = (x^{2} - 2 y) (1 + 4)$
$\Rightarrow (- x - y + 2)^{2} = 5 (x^{2} - 2 y) \Rightarrow 4 x^{2} - y^{2} - 2 x y + 4 x - 6 y - 4 = 0$