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Question

The equation to the straight line passing through the point (acos3θ,asin3θ) and perpendicular to the line xsecθ+ycosecθ=a is

A
xcosθysinθ=acos2θ
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B
xcosθ+ysin θ=acos2θ
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C
xsinθ+ycosθ=acos2θ
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D
None of these
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Solution

The correct option is C xcosθysinθ=acos2θ

Line perpendicular to xsecθ+ycosecθ=a is xcosecθysecθ=λ.
This line passes through the point (acos3θ,asin3θ).
Then,
(acos3θ)cosecθ(asin3θ)secθ=λ
λ=a(cos3θsinθsin3θcosθ)
=acos2θcosθsinθ
Hence, the equation of line is xcosθysinθ=acos2θ.


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