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Question

The equation to the tangent to (xa)n+(yb)n=2 at (a,b)

A
x+y=a+b
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B
xa+yb=2
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C
xa+yb=1
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D
xa+yb=4
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Solution

The correct option is A x+y=a+b
(xa)n+(yb)nn(xa)n1+n(yb)n1dydx=0
At point (a,b)
x=a , y=b
n+ndydx=0dydx=1=my=mx+cy=x+c
at(a,b)
b=a+c
c=b+a
y+x=b+a


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