The equation whose roots are cot22-7- cot24-7- cot28-7- cot2 6-7

t = tan^2 θ ∴ u = ^2 θ = 1t or t = 1u Putting in (6), we get #160; 7u^3 35u^2 + 21u 1 = 0. ∴ S_1 = co ...

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The equation ...

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The equation whose roots are
$c o t^{2} \frac{2 π}{7}, c o t^{2} \frac{4 π}{7}, c o t^{2} \frac{8 π}{7} (= c o t^{2} \frac{6 π}{7})$

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t a n^{2} \frac{2 π}{7}, t a n^{2} \frac{4 π}{7}, t a n^{2} \frac{8 π}{7} (= t a n^{2} \frac{6 π}{7})

c o s \frac{2 π}{7}, c o s \frac{4 π}{7} a n d c o s \frac{8 π}{7}

c o s \frac{2 π}{7}, c o s \frac{4 π}{7} a n d c o s \frac{6 π}{7}

c o s \frac{2 π}{4} c o s \frac{4 π}{7} c o s \frac{8 π}{7} = S_{3} = \frac{1}{8}

c o s \frac{2 π}{4} + c o s \frac{4 π}{7} + c o s \frac{8 π}{7} = S_{1} = - \frac{1}{2}

s e c \frac{2 π}{7}, s e c \frac{4 π}{7}, s e c \frac{8 π}{7} (= s e c \frac{6 π}{7})

7 + \sqrt{3}

7 - \sqrt{3}

2 cos \frac{π}{7}, 2 cos \frac{3 π}{7}, 2 cos \frac{5 π}{7}

m, n

x^{2} - 3 x + 5 = 0,

(m^{2} - 3 m + 7) & (n^{2} - 3 n + 7) =

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