The equation with a variable 5t - 4 = 1 is satisfied for 't' = 1.
Yes
In order to check whether the above equation is satisfied for t =1, we simply put 1 in place of t. So the equation upon putting 't' =1 becomes 5x1 - 4 = 1. Since LHS = 1 and RHS = 1.
So, t =1 satisfies the equation 5t-4 =1.