The equation with a variable 5t−4=1 satisfies for 't' = 1. State true or false.
Yes
In order to check whether the equation 5t−4=1 is satisfied for t =1, we simply put 1 in place of t.
As we know that a variable is a number which is not fixed and can take any given number like 1,2,3...
So, the equation upon putting 't' =1 becomes 5×1−4=1.
Here, LHS = 1 and RHS = 1.
Since LHS = RHS,
So, t = 1 satisfies the equation 5t−4=1.